Math, asked by nilaymcdonald, 1 year ago

find the values of p for which the quadratic equation x^2-px+p+3=0 has coincident roots​

Answers

Answered by KingNirbhay20
2

Answer:

Answer: p -2 & p 6 Step-by-step explanation: Find the value of p for which the quadratic equation x^2 px p+ 3-0 has a) coincident roots x - px p+3 O To have coincident roots 0 D b2 - 4ac for axbx c D 0 a 1 b p c (p +3) D (-p)2- 4(1)(p +3) D 0 p2- 4p 12 0 p2-6p+ 2p 12 0 p(p -6) 2(p -6) 0 + (p 2)(p -6)= p -2 & p 6 p -2x2 2x 1 0 = (x 1) 0 p 6 x2- 6x9 (x - 3)2 0

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