Find the values of the following
1) (2n)! ÷ n!
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Here is the solution..
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here is it
Step-by-step explanation:
1 - (2n - 1) = 1/(n / 1) * (1/2)(2/2)(3/2) ,...(n/2)(1/3.5...
= 1 n! (1.2*3...n)2^ n (1*3.5... (2n + 1)
= 1/(ni) * n!2 ^ n (1/3*5*...(2n-1))
= 2 ^ n * (1 * 3 * 5 * (- - (2n - 1)))
((2n)!)/(n!) = 1 n! (1/2*3*\ \ .2n).
= 1 n 1 *(2*4*6...2n)(1*3*5.... (2n - 1) )
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