Question

Find the values of the following when x=1,y=3 and z=4
1.(x-y-z²) with solution ​

Answer 1

Answer:

1) (1-3-(4^2) ) = (-2-16)= -18

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Answer 2

Answer:

(x-y-z²)

x = 1, y= 3, z = 4

= (1-3-(4)²)

= - 2-16

= - 18

Therefore ur answer is - 18

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