Question

find the values of the polynomial x^2+7x-3 when x= -1, 0 and 1

Answer 1

Answer:

x=1 =(1^2+7×1-3)=1+7-3=1+4=5

x=-1 =(-1^2+7×-1-3)=1-7-3=1-10=-9

x=0=(0^2+7×0-3)=0+0-3=-3

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