Find the values of the trigonometric function for the following: sin .
Answers
Answered by
2
Given, sin( 765°)
we can write , 765° = 720° + 45°
= 2 × 360° + 45°
so, sin(765°) = sin(2 × 360° + 45°)
we know, sin(n × 360° + x) = sinx , where n is an integer.
so, sin(2 × 360° + 45°) = sin45° = 1/√2
hence, sin(765°) = 1/√2
we can write , 765° = 720° + 45°
= 2 × 360° + 45°
so, sin(765°) = sin(2 × 360° + 45°)
we know, sin(n × 360° + x) = sinx , where n is an integer.
so, sin(2 × 360° + 45°) = sin45° = 1/√2
hence, sin(765°) = 1/√2
Similar questions