Find the values of the trigonometric function for the following: 
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Given, tan( 19π/3 )
tan( 19π/3 ) = tan{ (18π + π)/3 }
= tan{ 18π/3 + π/3 }
= tan{ 6π + π/3 }
= tan{2π.(3) + π/3 }
we know, tanx = tan(2nπ + x) , where n is integral number
so, tan{2π.3 + π/3} = tanπ/3 = √3
hence, tan(19π/3) = √3
tan( 19π/3 ) = tan{ (18π + π)/3 }
= tan{ 18π/3 + π/3 }
= tan{ 6π + π/3 }
= tan{2π.(3) + π/3 }
we know, tanx = tan(2nπ + x) , where n is integral number
so, tan{2π.3 + π/3} = tanπ/3 = √3
hence, tan(19π/3) = √3
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