find the values of trigonometry functions in exercises -
tan19π/3
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Step-by-step explanation:
ANSWER
(a) sin765
o
=sin(2(360)+45)=sin(45)
=
2
1
[∵sin(360+θ)=sinθ].
(b) csc(−1410
o
)=−csc(1410)
=−csc((360)3+330)
=−csc(330)
=−[−csc(270+60)]
=sec60
=2.
(c) tan
3
19π
=tan[
3
19
×180]=tan1140
=tan[(90×12)+60]
=tan60 [∵tan(90+θ)=tanθ]
=
3
.
(d) sin(
3
−11
π)=−sin(
3
11
π)
=−sin(4π−
3
1
π)
⇒−sin(
3
−1π
)=+sin
3
π
=
2
3
.
(e) cot(
4
−15π
)=−cot(
4
15π
)=−cot(4π−
4
π
)
=−cot(
4
−π
)
=cot(
4
π
)
=1.
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