Question

Find the values of x and y if (√2)/(3√6-√5) = x√3-y√10 .

Answer 1

x3=(1/2)3−(3(1/2))3x3=(1/2)3−(3(1/2))3

=>1/8−3(3)(1/2)=>1/8−3(3)(1/2)

2x2=2[(1/2)2−(3(1/2))2]2x2=2[(1/2)2−(3(1/2))2]

=>2[1/4−3]=>2[1/4−3]

=>−1=>−1

7x=7(1/2−(3)(1/2))7x=7(1/2−(3)(1/2))

=>7/2−7(3)(1/2)=>7/2−7(3)(1/2)

x3−2x2−7x+10becomes,x3−2x2−7x+10becomes,

=>1/8−3(3)(1/2)+1−7/2+7(3)(1/2)+10=>1/8−3(3)(1/2)+1−7/2+7(3)(1/2)+10

=>4(3)(1/2)+61/8