find the values of x and y,if two ordered pairs (x-2,5) (5,x-y) and equal
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3^2+4^2=5^2=25
Putting x-y=3,x=4, we have (4,1)
x^2+(x-y)^2=5^2
We can consider x,x-y,5 as the sides of a right angled triangle with hypotenuse 5
From triangle inequalities,
x+5>=x-y or,y>=-5
According to question y>=0…..(1)
Again, x+x-y>=5 or, 2x-y>=5 or, 2x-5>=y
From (1), 2x-5>=0 or, x>=2.5
x>=3
Similarly, we can obtain y<=5
Another possible solution is (5,5)
So, possible solutions according to me are (4,1) and (5,5)
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