Question

find the values of x³+x²-x+22 when x=1+2i

Answer 1

this is answer.....d..d.d.d.d.d.d.

Answer 2

The given question is we have to find the values of x³+x²-x+22

when x=1+2i.

the value of x given here is an imaginary value.

The value of a function at a certain point is referred to a value of a function,

this is obtained if we plug in the given values for the variables that present in the function.

The given expression is

${x}^{3} + {x}^{2} - x + 22$

we have to substitute

$x = 1 + 2i$

substitute the above value in the places of x, in the above expression.

${(1 + 2i)}^{3} + {(1 + 2i)}^{2} - ( 1 + 2i) + 22$

$(1 + {8i}^{3} + 3(2i) + 3( {2i})^{2} ) + (1 + {4i}^{2} + 4i) - (1 + 2i) + 22$

simplifying the above expression we get,

$1 - 8i + 6i - 12 + 1 - 4 + 4i - 1 - 2i + 22$

separate the like terms and solve.

$- 8i+ 6i + 4 i- 2i - 12 - 1 - 4 + 1 + 1 + 22$

now simplify the like terms we get

$- 10i + 10i - 17 + 24 \\ 0i + 7 = 7$

The final answer is 7.

Therefore, the value of the given expression on Substituting x=1+2i is 7.

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