Question

pls answer the circled question

Answer 1

Let the three consecutive numbers be x + 1,x + 2,x + 3.

Given that sum of second and the third number exceeds the first term by 14.

= > x + 2 + x + 3 = x + 1 + 14

= > 2x + 5 = x + 15

= > 2x - x = 15 - 5

= > x = 10.

Then,

= > x + 1 = 11

= > x + 2 = 12

= > x + 3 = 13.

Therefore, the three numbers are 11,12,13.

Hope this helps!