find the values of y for which distance between (2,3) and (0,1) is 10 units
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Hey !!!!!
let A( 2,3 ) and B(y,1) be the given points.
Here AB = 10 units given
Therefore by distance formula
AB = √ ( x1-x2)²+(y1-y2)²
10 = √ (2 - y)²+(3 - 1)²
Square both sides
100 = 4 + y² - 4y + 4
92 = y² - 4y
y² - 4y - 92 = 0
By completing the square method,
y² - 4y= 92
y² - 4y + 4 = 92 + 4
( y - 2)² = 96
Now You can solve it
let A( 2,3 ) and B(y,1) be the given points.
Here AB = 10 units given
Therefore by distance formula
AB = √ ( x1-x2)²+(y1-y2)²
10 = √ (2 - y)²+(3 - 1)²
Square both sides
100 = 4 + y² - 4y + 4
92 = y² - 4y
y² - 4y - 92 = 0
By completing the square method,
y² - 4y= 92
y² - 4y + 4 = 92 + 4
( y - 2)² = 96
Now You can solve it
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