Question

Find the values of y for which the distance between the points P (2, -3) and Q (10, y) is 10 units.

Answer 1

Answer:

3

Step-by-step explanation:

d=√(x2-x1)^2 + (y2-y1)^2

10=√(10-2)^2+(y+3)^2

10=√64+(y+3)^2

squaring both side

100 = 64 + (y+3)^2

y+3=6

y=3 ans

Answer 2

Given : Distance between the points P (2, -3) and Q (10, y) is 10 units.

 

To prove : Find the values of y .

Solution is in the attachment below .

We use the distance formula : √(x2 - x1)² + (y2 - y1)² and this identity to solve this question (a + b)² = a² + b² + 2ab

Hence , the values of y is 3 and - 9.

Some important information :  

• Coordinate geometry is the branch of mathematics which deals with the position of an object lying in a plane.
• Each  point in cartesian plane has two coordinates X coordinate and Y coordinate.
• The X co-ordinate is called the abscissa.
• The Y co-ordinate is called the ordinate.
• Coordinates X and Y taken together are called coordinates of a point. (x,y) is called an ordered pair.

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