Question

find the values of y for which the distance between
the points
P(2,-3) and Q（10 y）is 10 units.​

Answer 1

Answer:

P(2,-3);Q(10,y)

√(10-2)^2+(y+3)^2=10

√(10-2)^2+√(y+3)^2=10

(10-2)+(y+3)=10

8+y+3=10

11+y=10

y=10-11

y=-1

Step-by-step explanation:

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Answer 2

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