Question

Find the values of y for which the distance between the points P2. - 3) and o
(10. y) is 10 units.​

Answer 1

Answer:

Step-by-step explanation:

PQ=$\sqrt{(x2-x1)^2+(y2-y1)^2$

  10 =$\sqrt({10-2)^2+(y-(-3))^2$

(10)^2=64-(y+3)^2

100=64-(y^2+9+6y)

100=64-y^2-9-6y

100=55-y^2-6y

y^2+6y=55-100

y^2+6y=-45

using discriminant method

i.e,     d=b^2-4ac

            =6^2-4*1*45

              =12- 180

               =-168