Question

find the valve of K for which roots are real and equal in the equation X^2 - 2 ( k +1)x+k^2 = 0​

Answer 1

Answer:

k = -1/2

Step-by-step explanation:

Given x^2 - 2 (k+1) x + k^2 = 0 has real and equal roots

As we know that

for a quadratic equation to have real and equal roots, discriminant should be zero

= {-2(k+1)}^2 - 4 (1) (k)^2 = 0

= (k+1)^2 - k^2 = 0

= 2k + 1 = 0

= k = -1/2