Question

find the valye of k for which the quadratic equation k-12 x2+2 k-12 x+2=0​

Answer 1

Answer:

k-12x2+2k-12×+2=0

(k-12)X2+2(k-12)×+2=0

ax2+bx+c=0

Step-by-step explanation:

b2-4ac

[2(k-12)]2-4(k-12)(2)

(2k-24)2- 8(k-12)

4k2 -96k+576-8k+96

4k2-104k+672

The roots of given equation are real and equal

triangle must be zero

4k2-104k+672=0

4(k2-26k+168)=0

k2-14k -12k+168=0

k(k-14)-12(k-14)=0

(k-14) (k-12) =0

k-14=0 or k-12=0

k=14or k=12