find the variance of first 10 natural number
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Step-by-step explanation:
var (1,2,3.........n)=10 (given)
formula {σ
2
=
N
∑f
i
d
i
2
−(
N
∑f
i
d
i
)
2
⇒
n
1
2
+2
2
+−−−−−−−−+n
2
+(
2
n+1
)
2
=10
⇒
2
n+1
[
3
2n+1
−
2
n+1
]=10
⇒
2
n+1
[
6
4n+2−3n−3
]=10
⇒
2
n+1
[
6
n−1
]=10
⇒n
2
−1=120
⇒n=11
and,
var(2,4,6........2m)=16
⇒4var(1,2,3..........,m)=16
⇒var(1,2,3........,m)=4
⇒
12
m
2
−1
=4
⇒m
2
−1=48
⇒m=7
∴m+n=11+7=18
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