Question

Find the velocitf oi impact oi an object with suriace oi earth afer throwing with 2m/s inital speed to the height 6m, afer rsec. (Take g = 10m/s2)​

Answer 1

Answer:

$\huge\red{Anwer}$

Velocity half second before maximum height

=

Velocity half second after maximum height (Return journey)

For downward journey :

Initial velocity

u=

0 m/s

We have

g=

9.8 m/s

2

Time

t=

2

1

s

Thus velocity after half second

v=

u+

gt

v=

0+

9.8×

2

1

=

4.9m/s .

Thank u