Question

find the velocity acquired by an electron in falling through a potential difference of 2000 volts.​

Answer 1

potential difference , V = 2000 volts

charge on electron, q = 1.6 × 10^-19 C

mass of electron, m = 9.1 × 10^-31 kg

now using law of conservation of energy theorem,

kinetic energy of electron = workdone on electron in potential difference 2000volts

or, 1/2 mv² = qV

or, 1/2 × 9.1 × 10^-31 v² = 1.6 × 10^-19 × 2000

or, 4.55 × 10^-31 v² = 3200 × 10^-19

or, v² = (3200/4.55) × 10¹²

or, v = 26.51 × 10^6 m/s

hence, velocity of electron is 2.651 × 10^7 m/s