Question

find the velocity of a bullet of mass 5kg which is fired feom a pistol of mass 2kg.recoil velocity of pistol is 1.5 m/s​

Answer 1

Answer:

5×1.5= 2 × V2

3.75 =V2

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Answer 2

Explanation:

Total momentum initial,zero

Final momentum 150 × 20/1000+(—2×v) = 0 (the initial momentum)

2v = 3

V =3/2 m/s

V= 1.5m / s the recoil Vel. in the opposite direction of the bullet