Find the velocity of a projectile at the highest point if it is projected with a speed of 15 m per second in the direction 45 degree above horizontal take g is equal to 10 metre per second square
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7.88ms-1
Explanation:
In a projectile motion,at the highest point the vertical component of velocity is zero but the horizontal component is same as the original horizontal component of initial velocity..Hence,velocity at the highest point is the horizontal component of initial velocity which is 15cos45=7.88
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