Find the velocity of bullet of mass 5g which is fired from a pistol of mass 1.5g. The recoil velocity of pistol is 1.5ms⁻¹.
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Answer:
0.45m/s
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Mass of bullet (m) = 5 g
Mass of pistol (m) = 1.5 g
Initial velocity of pistol and bullet = 0 m/s
[u = u = 0]
Recoil velocity of pistol (v) = 1.5 m/s
Let recoil velocity of bullet = v
Law of conservation of Momentum:
The overal momentum before collision of 2 objects and after collision remains constant if no external unbalanced force acts on them.
Mathematically,
mu + mu = mv + mv
(5 g)(0 m/s) + (1.5 g)(0 m/s) = (5 g)v + (1.5 g)(1.5 m/s)
5v + 2.25 = 0
5v = - 2.25
v = - 0.45 m/s.
(Negative sign indicates the velocity of bullet is opposite to that of the pistol.)
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