Question

Find the velocity with which a ball is thrown up if it reaches maximum height in 5 sec. Find its maximum height

Answer 1

Hey Mate
Here in this Question To Find Velocity we use:-

Vfinal = Vinitial - g × t
0 = Vintial - 10×5
Vintial = 50 m/s^-1

Now to find the Maximum Height

$h = {u}^{2} \sin(90) \div 2g$
here Teta=90 because at 90° we can find the maximum height.

Here U=50, g=10

we get finally

H= 125 m

Answer 2

it may help you.....................