Question

Find the voltage drop across 18 Ω resistor in the given circuit

Answer 1

in series : r = 6+12
= 18
in parallel
1/r = 1 /6 + 1/18
= 1/18 ( 3 + 1 )
= 1/18×4
= 9/2
in series
R = 18 + 9/2
= 1/2 ( 36 + 9 )
= 45/2 ohm

current
I = V/ R
= 30÷45/2
= 60÷ 45
= 4÷3
= 1.6 A
potential at 18 ohm
v = I × R
= 4/3 ×18
= 24 volt.

Answer 2

Answer:

24 volt.

Explanation:

in series : r = 6+12

= 18

in parallel

1/r = 1 /6 + 1/18

= 1/18 ( 3 + 1 )

= 1/18×4

= 9/2

in series

R = 18 + 9/2

= 1/2 ( 36 + 9 )

= 45/2 ohm

current

I = V/ R

= 30÷45/2

= 60÷ 45

= 4÷3

= 1.6 A

potential at 18 ohm

v = I × R

= 4/3 ×18

= 24 volt.