Question

find the volume and the total surface area of a closed right cylinder whose radius is 0.7m and height is 10m.

Answer 1

T. S. A = 2pie r h + pie r²
=2 × 22 /7 × 7/10 × 10 + 22/7 × 0.49
=44 + 0.22 = 44.22m².


Volume = pie r² h
= 22/7 × 7/10 × 7/10 × 10
= 15.4m³.



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Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\therefore{\text{Volume\:of\:cylinder=15.4\:m}^{3}}}$

$\green{\therefore{\text{T.S.A\:of\:cylinder=47.08\:m}^{2}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{ \underline \bold{Given : }} \\ : \implies \text{Radius(r) = 0.7\: m} \\ \\ : \implies \text{Height(h) = 10 \: m} \\ \\ \red{ \underline \bold{To \: Find : }} \\ : \implies \text{Volume \: of \: cylinder = ? }\\ \\ : \implies \text{T.S.A\: of \: cylinder = ? }$

• According to given question :

$\bold{As \: we \: know \: that} \\ : \implies \text{Volume\: of \: cylinder} =\pi r^{2}h \\ \\ : \implies \text{Volume\: of \: cylinder} = \frac{ 22}{7} \times {0.7}^{2}\times 10 \\ \\ : \implies \text{Volume\: of \: cylinder} =22 \times 0.07\times 10 \\ \\ \green{ : \implies \text{Volume\: of \: cylinder} =15.4\: {m}^{3}} \\ \\ \bold{As \: we \: know \: that} \\ : \implies \text{T.S.A\: of \: cylinder} =2\pi r(h + r) \\ \\ : \implies \text{T.S.A\: of \: cylinder} =2 \times \frac{22}{7} \times 0.7(10+ 0.7) \\ \\ : \implies \text{T.S.A\: of \: cylinder} =2 \times 22 \times \\ \\ \green{ : \implies \text{T.S.A\: of \: cylinder} =47.08 \: {m}^{2} }$