Question

find the volume at STP of 8.0g of O2

Answer 1

mole = mass given/molar mass

mole= volume given/22.4

molar mass of O2= 16*2g

mass given=8g

mass given/molar mass= volume given/22.4

8/32=volume given/22.4

volume given = 8 * 22.4/32

                     = 5.6L

Answer 2

=8*22.4/32

=5.6 L volume at stp.