find the volume at STP of 8.0g of O2
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Answered by
4
mole = mass given/molar mass
mole= volume given/22.4
molar mass of O2= 16*2g
mass given=8g
mass given/molar mass= volume given/22.4
8/32=volume given/22.4
volume given = 8 * 22.4/32
= 5.6L
Answered by
0
=8*22.4/32
=5.6 L volume at stp.
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