Math, asked by MdJaid, 10 months ago

find the volume curved surface area and total surface area of the cylinder whose height and radius of the base are 28 cm and 3 cm respectively​

Answers

Answered by BrainlyPromoter
5

Answer:

(1) Volume = 682 cm³

(2) Curved Surface Area = 528 cm²

(3) Total Surface Area = 584.57 cm²

Step-by-step explanation:

Information provided to us-

1. Radius of the base of the cylinder = 3 cm

2. Height of the cylinder = 28 cm

Let us denote radius of the base of the cylinder by 'r' and the height of the cylinder by 'h'.

Hence,

r = 3 cm

h = 28 cm

We know that, volume of cylinder is,

\pi \: r {}^{2} h \\

Substituting the values in the above formula,

\pi {(3)}^{2}  \times 28 \\  = 9\pi \times 28 \\  = 252\pi \\  = 252 \times  \frac{22}{7}  \\  \\  = 31 \times 22 \\  = 682 \: cm {}^{3}

We know that, the curved surface area of a cylinder is,

2\pi \: rh

Substituting the values in the above formula,

2\pi \times 3 \times 28 \\  = 2 \times  \frac{22}{7}  \times 3 \times 28 \\  \\  = 44 \times 3 \times 4 \\  = 44 \times 12 \\  = 528 \: cm {}^{2}

We know that, the total surface area of a cylinder is,

2\pi \: r(r + h)

Substituting the values in the above formula,

2\pi  \times 3(3 + 28) \\  = 2\pi \times 3 \times 31 \\  = 2\pi \times 93 \\  = 186\pi \\  = 186 \times  \frac{22}{7}  \\  \\  =  \frac{4092}{7}  \\   \\  = 584.57 \: cm {}^{2}

Similar questions