Math, asked by irimiaamichelle, 1 year ago

Find the volume of a cone with slant equal to 10m and radius equal to 8m.


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Answers

Answered by MoirangthemJohnson
1

the reqd. vol. of a cone is 402.2857142857.

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Answered by abdul9838
1

Hey user here is Answer

according to question.

given that

slant of cone(l)=10 cm

Radius of cone (r)=8 cm

as we know that

volume of cone=1/3πr^2h

so we have to find the value of h

it means

h=?

now

using to this formula

 \bf \red{  {l}^{2}  =  {r}^{2}  +  {h}^{2} } \\  \\  \bf \blue{ {10}^{2}  =  {8}^{2} +  {h}^{2}  } \\  \\  \bf \red{100 - 64 =  {h}^{2} } \\  \\  \bf \red{ {h}^{2}  = 36} \\  \\  \bf \red{h =  \sqrt{36} } \\  \\  \bf \red{h = 6 \: cm} \\  \\  \bf \huge \: now \\  \\  \bf \blue{using \: to \: this \: formula} \\  \\  \bf \pink{volume \: of \: cone =  \frac{1}{3} \pi \:  {r}^{2}h } \\  \\  \bf \pink{v =  \frac{1}{3} \times  \frac{22}{7}   \times 8 \times 8 \times 6} \\  \\  \bf \pink{v =  \frac{22 \times 64 \times 2}{7} } \\  \\  \bf \pink{v =  \frac{44 \times 64}{7} } \\  \\  \bf \pink{v =  \frac{2816}{7} } \\  \\  \bf \pink{v = 402.28} \\  \\  \bf \pink{v = 402.3 \:  c {m}^{3} \:  \:  \: approx}

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