Question

find the volume of a cylinder where the area of its base is 45 CM square and height 9 CM​

Answer 1

$\underline{\mathfrak{\huge{The\:Question:}}}$

Find the volume of a cylinder where the are of its base is $\tt{45cm^{2}}$ and height is 9 cm.

$\underline{\mathfrak{\huge{Your\:Answer:}}}$

We're Given that :-

Area of the base of the cylinder = $\tt{45 cm^{2}}$

Height of the cylinder = $\tt{9 cm}$

---

Area of a circle = $\tt{\pi r^{2}}$

=》 45 = $\tt{\pi r^{2}}$

=》 $\tt{r^{2} = \frac{45}{\pi}}$

To make our calculations simpler for the rest of the problem ( problem here, means question ), we can leave the value upto this only, as we know that :-

Volume of a cylinder = $\tt{\pi r^{2} h}$

Therefore, we can have the value of $r^{2}$ only and not simplify it further.

Volume of cylinder = $\tt{\pi r^{2} h}$

Put the values in this formula and then solve the obtained equation :-

Volume = $\tt{\pi \times \frac{45}{\pi} \times 9}$

Volume = $\tt{45 \times 9}$

Volume = $\tt{405 cm^{3}}$

Answer 2

$\sf{\huge{Question}}$

Find the volume of a cylinder where the area of its base is 45 cm square and height 9 cm.

$\sf{\huge{Brainliest \: Solution}}$

Given,
Area of base = 45 cm²
Height = 9 cm

Find,
Volume of Cylinder = ?

$\sf{\large{Step \: 1.}}$

First find the Radius

$\sf Area \: of \: base = \pi r {}^{2} \\ \sf 45 = \pi r {}^{2} \\ \sf \frac{45}{\pi} = {r}^{2}$

$\sf{\large{Step \: 2.}}$

Find the Volume

$\sf Volume \: of \: cylinder = \pi r {}^{2} h \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf= \cancel\pi \times \frac{45}{ \cancel\pi} \times 9 \\ \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \sf =405 \: cm {}^{3}$