Question

find the volume of a cylinder whose height is 10 cm and radius of base is 5 (π = 3.14)​

Answer 1

Answer:

is it correct? kindly reply for it.

Answer 2

$\bf \: \underline{Given} :$ ↴

$\sf \: Height = 10 \: cm$

$\sf \: Radius \: of \: base = 5 \: cm$

$\sf \: [Note = \pi = 3.14]$

$\bf \: \underline{To \: find} :$ ↴

$\sf \: We \: have \: to \: find \: the \: volume \: of \: a \: cylinder.$

$\bf \: \underline{ \underline{Solution}} :$ ↴

$\sf \: As \: we \: know \: that,$

$\boxed{ \pink{\sf \: Volume \: of \: cylinder = \pi \: r^{2} \: h }}$

$\sf \implies \: 3.14 \times (5 \: cm^{2} ) \: \times 10 \: cm$

$\sf \implies \: 3.14 \times 25 \: cm \: \times 10 \: cm$

$\sf \implies \: 3.14 \times 250 \: cm$

$\sf \implies \: 785 \: cm ^{3}$

$\sf \boxed{\red{ \sf \: So, \: volume \: of \: cylinder = 785 \: cm ^{3} }}$

$\setlength{\unitlength}{1mm}\begin{picture}(5,5)\thicklines\multiput(-0.5,-1)(26,0){2}{\line(0,1){40}}\multiput(12.5,-1)(0,3.2){13}{\line(0,1){1.6}}\multiput(12.5,-1)(0,40){2}{\multiput(0,0)(2,0){7}{\line(1,0){1}}}\multiput(0,0)(0,40){2}{\qbezier(1,0)(12,3)(24,0)\qbezier(1,0)(-2,-1)(1,-2)\qbezier(24,0)(27,-1)(24,-2)\qbezier(1,-2)(12,-5)(24,-2)}\multiput(18,2)(0,32){2}{\sf{5 cm}}\put(9,17.5){\sf{10 cm}}\end{picture}$

$\sf See\: the \: above \:diagram\: for\: the \: better \: understanding.$

$\bf \: \underline{Some \: important \: terms}:$ ↴

$\sf \:1. \: Volume \: of \: Cylinder = \pi \: r^{2} \: h$

$\sf \: 2. \: Total \: Surface \: Area \: ( TSA ) \: of \: cylinder = 2 \pi \: r ( r + h )$

$\sf \:3. \: Curved \: Surface \: Area \: ( CSA ) \: of \: cylinder = 2 \pi \: r \: h$

$\sf \: 4. \: The \: value \: of \: \pi \: is \: \dfrac{22}{7} \: or \: 3.14 \: in \: decimal.$

$\sf \: \underline{You \: can \: remember \: these \: formula \: also.} \:$

$\begin{gathered}\begin{array}{c|c|c}\cline{1-3}\bf Shape&\bf Volume\ formula&\bf Surface\ area formula\\\cline{1-3}\sf Cube&\tt l^3}&\tt 6l^2\\\cline{1-3}\sf Cuboid&\tt lbh&\tt 2(lb+bh+lh)\\\cline{1-3}\sf Cylinder&\tt {\pi}r^2h&\tt 2\pi{r}(r+h)\\\cline{1-3}\sf Hollow\ cylinder&\tt \pi{h}(R^2-r^2)&\tt 2\pi{rh}+2\pi{Rh}+2\pi(R^2-r^2)\\\cline{1-3}\sf Cone&\tt 1/3\ \pi{r^2}h&\tt \pi{r}(r+s)\\\cline{1-3}\sf Sphere&\tt 4/3\ \pi{r}^3&\tt 4\pi{r}^2\\\cline{1-3}\sf Hemisphere&\tt 2/3\ \pi{r^3}&\tt 3\pi{r}^2\\\cline{1-3}\end{array}\end{gathered}$