Find the volume of a right circular cylinder whose curved surface area iso 2640cm cube and circumference of the Base is 66 cm
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Heya,
According to the question,
Curved surface area of right circular cylinder= 2640cm²
Circumference = 66cm
Therefore,
2πr = 66
2 × 22/7 × r = 66
r = (66 × 7)/(22 × 2)
r = 10.5
Therefore, radius of right circular cylinder = 10.5 cm
As,
CSA = 2640cm²
Therefore,
2πrh = 2640
2×22/7×10.5×h = 2640
h = (2640×7)/2×22×10.5
h = 18480/462
h = 40
So, height of right circular cylinder = 40cm
Therefore,
Area of right circular cylinder = πr²h
= 22/7 × 10.5 × 10.5 × 40
= 97020/7
= 13860 cm³
Therefore area of right circular cylinder = 13860 cm³
Hope this helps....:)
According to the question,
Curved surface area of right circular cylinder= 2640cm²
Circumference = 66cm
Therefore,
2πr = 66
2 × 22/7 × r = 66
r = (66 × 7)/(22 × 2)
r = 10.5
Therefore, radius of right circular cylinder = 10.5 cm
As,
CSA = 2640cm²
Therefore,
2πrh = 2640
2×22/7×10.5×h = 2640
h = (2640×7)/2×22×10.5
h = 18480/462
h = 40
So, height of right circular cylinder = 40cm
Therefore,
Area of right circular cylinder = πr²h
= 22/7 × 10.5 × 10.5 × 40
= 97020/7
= 13860 cm³
Therefore area of right circular cylinder = 13860 cm³
Hope this helps....:)
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