Question

find the volume of a solid in a form of a right circular cylinder with hemispherical ends whose extreme length is 22 cm and diameter is 3 cm

Answer 1

volume of 2 hemisphere = 2/3πr³×2
= 2/3×22/7×1.5³×2
= 14.14cm³
volume of cylinder = πr²h
= 22/7×1.5²×(22-3)
= 134.35cm³
volume of whole cylinder = 134.35+14.14
= 148.49cm³
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Answer 2

The volume of solid is 148.5 sq.cm.

Step-by-step explanation:

A solid in a form of a right circular cylinder with hemispherical ends

Length of Solid = 22 cm

Diameter of hemisphere = 3 cm

Radius of hemisphere = $\frac{3}{2} = 1.5 cm$

Height of 2 hemispheres = 1.5+1.5 = 3 cm

Height of cylinder = Total Height - Height of 2 hemispheres

Height of cylinder = 22-3=19 cm

Volume of solid = Volume of cylinder + Volume of 2 hemispheres

Volume of solid =$\pi r^2 h + 2 (\frac{2}{3} \pi r^3)$

Volume of solid =$\frac{22}{7} \times 1.5^2 \times 19+2 \times \frac{2}{3} \times \frac{22}{7} \times 1.5^3=148.5 cm^3$

Hence The volume of solid is 148.5 sq.cm.

#Learn more:

Find the volume and surface area of a solid in the form of a right circular cylinder with hemispherical ends whose extreme length is 21 dm and diameter is 2.5 dm.​

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