Question

Find the volume of CO (at S.T.P.) required to react 0.25 mole ferric oxide (Fe.O.) as per the given equation
(1) 16.8 dm3
(2) 67.2 dm3
(3) 22.4 dm3
(4) 44.8 dm3

Fe2Co3 + 3Co --- 2Fe + 3Co2​

Answer 1

Answer:

(1) 16.8 dm3

Explanation:

chemical reaction of ferric oxide and carbon monoxide follows as ;

     Fe2O3 + 3CO → 2Fe +3CO2

here it is clear that 1 mole of Fe2CO3 react with 3 moles of CO.

so, 0.25 mole of Fe2O3 reacts with 3 × 0.25 = 0.75 mole of CO.

we know,

volume of one mole of gas at STP (standard temperature and pressure)

= 22.4 L

so, volume of CO

= no of mole of CO × 22.4L

= 0.75 × 22.4

= 16.8 L

hence, 16.8L of CO at S.T.P required to reduce 0.25 mole ferric oxide.