Question

Find the volume of CO2 obtained at S.T.P.on heating 200 gm of 50% pure CaCO3 -(A) 11.2 litre (B) 22.4 litre(C) 44.8 litre(D) None of these​

Answer 1

Answer:

  Calculate the number of moles, and number if atoms of H, S, and O in 5 mole of H2SO4.

Explanation:

Answer 2

Volume of CO₂

Given: 200 gm of 50% pure CaCO₃

The correct answer is: (B) 22.4 litre

Explanation:

• Equation: CaCO₃ ⇌ CaO + CO₂
• One mole of calcium carbonate on decomposition gives one mole of carbon dioxide and one mole calcium oxide.
• The molecular weight of calcium carbonate (CaCO₃) is 100g/mol.
• 200g calcium carbonate corresponds to 2 mol.
• Decomposition of calcium carbonate will give 2 mol of carbon dioxide.
• As given CaCO₃ is only 50% pure. Hence, 1 mol of carbon dioxide will be obtained.
• 1 mole of carbon dioxide occupies 22.4 L at STP.
• Hence, 1 mol of carbon dioxide will occupy 1×22.4= 22.4 L.