Question

Find the volume of cubical box whose surface area is 486

Answer 1

Answer:-

V = 729cm³

Given :-

Surface area of cubical box = 486 cm²

To find :-

The volume of cubical box.

Answer:-

We know that the total surface of area of cube is given by :-

★ $\boxed{\sf{TSA = 6(side)^2}}$

Now, put the value,

→$486 = 6(side) ^2$

→$(side) ^2 = \dfrac{486}{6}$

→$(side)^2 = 81$

→$side = \sqrt{81}$

→$side= 9 cm$

Now, Volume of cube is given by :-

★ $\boxed{\sf{V = (side) ^3}}$

→$V = (9) ^3$

→$V = 729 cm^3$

hence,

The volume of cubical box is 729 cm³.

Answer 2

Answer:

V = 729cm³

Step-by-step explanation:

Given Problem:

Find the volume of cubical box whose surface area is 486.

Solution:

To Find:

The volume of cubical box.

-----------------------

Method:

Given that,

Surface area of cubical box = 486 cm²

We know that:

$\implies\ TSA = 6(side)^2$

Now,

$\rightarrow\ 486 = 6(side)^2$

$\rightarrow\ (side)^2 = \dfrac{486}{6}$

$\rightarrow\ (side)^2 = 81$

$\rightarrow\ side = \sqrt{81}$

$\rightarrow\ side = 9cm$

We also know that,

$\implies\ V = (side)^3$

Now,

$\rightarrow\ V =(9)^3$

$\rightarrow\ V =729\:cm^3$

Therefore,

The volume of cubical box is 729 cm³.