Question

find the volume of given figure.​

Answer 1

Answer:

Step-by-step explanation:

first figure is frustum and another one is cone

Answer 2

The volume of the given figure is $\dfrac{398}{3}\ m^3$.

Explanation:

Given , radius of base of frustum : r = 2m

Radius of cone : R= 3 m

Height of cone : H= 7m

Total height of figure = 10.5 m

Height of frustum : h = 10.5-7 = 3.5 m

Volume of given figure = (Volume of frustum) + (Volume of cone)

$=\dfrac{1}{3}\pi H(r^2+R^2+rR) + \dfrac{1}{3}\pi R^2 H\\\\=\dfrac{1}{3}\pi ( h(r^2+R^2+rR)+R^2H)\\\\=\dfrac{1}{3}\times\dfrac{22}{7}((3.5)(2^2+3^2+(2)(3)+(3)^2(7))\\\\=\dfrac{398}{3}\ m^3$

Hence, the volume of the given figure is $\dfrac{398}{3}\ m^3$.

# Learn more :

Find the volume of the sphere given in the adjacent figures

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