find the volume of iron required to make an open box whose external dimensions are 36 cm *25 cm *16.5 cm, the box being 1.5 cm thick throughout. If 1 cm cube of iron weighs 8.5 grams, find the weight of the empty box in kilograms.
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Thickness of the box=1.5cm
Therefore internal dimension will be
len=33cm
breadth=22cm
height =15cm
External volume=36*25*16.5=14850cm3
Internal volume=22*33*15=10890cm3
Volume used in make the box=14850-10890=3960cm3
Weight of 1 cm3 of iron=8.5g
so the total weight of iron will be 8.5*3960=33600g=33.6 kg
Therefore internal dimension will be
len=33cm
breadth=22cm
height =15cm
External volume=36*25*16.5=14850cm3
Internal volume=22*33*15=10890cm3
Volume used in make the box=14850-10890=3960cm3
Weight of 1 cm3 of iron=8.5g
so the total weight of iron will be 8.5*3960=33600g=33.6 kg
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