prove that the bisectors of opposite angles a parallelogram are parallel
Answers
Answered by
2
In the given figure we have DL parallel to BM and BL and DM are two transversals then,
∠DLB + ∠LBM = 180° and ∠LDM + ∠DMB = 180°
⇒ ∠DLB = 180° - ∠LBM and
∠DMB = 180° - ∠LDM .... (3)
As proved earlier ∠LBM = ∠LDM
Therefore, ∠DLB = 180° - ∠LDM ... (4)
Now, on comparing (3) and (4), we get
∠DMB = ∠DLB
Therefore, LDMB is a parallelogram as its opposite angles are equal.
∴ BL || DM
∠DLB + ∠LBM = 180° and ∠LDM + ∠DMB = 180°
⇒ ∠DLB = 180° - ∠LBM and
∠DMB = 180° - ∠LDM .... (3)
As proved earlier ∠LBM = ∠LDM
Therefore, ∠DLB = 180° - ∠LDM ... (4)
Now, on comparing (3) and (4), we get
∠DMB = ∠DLB
Therefore, LDMB is a parallelogram as its opposite angles are equal.
∴ BL || DM
Anshika111111111:
i asked to prove it parallel
Answered by
23
In this picture , ABCD is a parallelogram in which
AX and CY bisects opposite angle A and angle B respectively .
It has also been proved that these two bisectors are parallel .
Hope that it will be useful for you ....
Wherever you get any confusion related with the written answer .....you can ask me in the comment box .
AX and CY bisects opposite angle A and angle B respectively .
It has also been proved that these two bisectors are parallel .
Hope that it will be useful for you ....
Wherever you get any confusion related with the written answer .....you can ask me in the comment box .
Attachments:
Similar questions