Math, asked by Anshika111111111, 1 year ago

prove that the bisectors of opposite angles a parallelogram are parallel

Answers

Answered by Ayesha059
2
In the given figure we have DL parallel to BM and BL and DM are two transversals then,

∠DLB + ∠LBM = 180° and ∠LDM + ∠DMB = 180°

⇒ ∠DLB = 180° - ∠LBM and

∠DMB = 180° - ∠LDM  .... (3)

As proved earlier ∠LBM = ∠LDM

Therefore, ∠DLB = 180° - ∠LDM  ... (4)

Now, on comparing (3) and (4), we get

∠DMB = ∠DLB

Therefore, LDMB is a parallelogram as its opposite angles are equal.

∴ BL || DM

 

Anshika111111111: i asked to prove it parallel
Ayesha059: now?
Answered by AlinaKovapi
23
In this picture , ABCD is a parallelogram in which

AX and CY bisects opposite angle A and angle B respectively .


It has also been proved that these two bisectors are parallel .

Hope that it will be useful for you ....

Wherever you get any confusion related with the written answer .....you can ask me in the comment box .
Attachments:

AlinaKovapi: Sorry ....that's angle C not B being bisected by CY
AlinaKovapi: But in d picture ...it's all right
Anshika111111111: yes
Anshika111111111: thanks
AlinaKovapi: ur welcome
AlinaKovapi: Thanks for selecting my answer as the brainliest
Anshika111111111: ur welcome
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