Question

find the volume of of iron required to make an open box who external dimensions are 36 cm into 25 cm into 16.5 cm the box being 1.5 centimetre thick throughout.If 1 cubic centimetre of iron weights 8.5 grams, find the weight of the empty box in kilograms​

Answer 1

Answer:

the external dimensions of the rectangular box =36cm*25cm*16.5cm

external volume of the box = 14850 cubic cm

since the thickness of the box is 1.5 cm and box is open.

internal length = (36-1.5*2)cm= 36-3=33 cm

internal breadth = 25-1.5*2=25-3=22 cm

internal height = 16.5-1.5 = 15 cm [since box is open]

therefore the internal dimensions of the rectangular box= 33cm*22cm*15cm

internal volume of the box = 10890 cubic cm

therefore the volume of the iron = external volume of the box - internal volume of the box

= 14850-10890

=3960 cubic cm

since 1 cubic cm of iron weighs 8.5 grams.

therefore weight of 3960 cubic cm = 3960*8.5=33660 gm

i.e. the weight of the empty box is 33.66 kg.

hope this helps uh...

Answer 2

Answer:

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