Question

Find the volume of stp of 6.022*10^23 molecule of ammonia

Answer 1

Given moleules of NH3 = 6.022*10^23

moles of NH3 = 6.022*10^23 / 6.022*10^23 = 1 mol

1 mol of NH3 = 6.022*10^23 molecules = 22.4L at STP