find the volume of the box whose dimensions are 3xy², 1/7x³and 5/5x²y
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Answered by
4
Answer:
volume of the box = (3xy^2)*(1/7x^3)*(5/5x^2y)
= 3/7x^6y^3
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0
Answer:
3x⁶y³/7
Explanation:
length =3xy²
breadth=1/7x³
height=5/5x²y
volume=length×breadth × height
=3xy²×1/7x²×x²y
=3x⁶y³/7
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