find the volume of the iron used to make a closed box of outer dimensions 15 cm × 12 cm × 9 cm, the thickness of the iron being 0.8 cm all around.
please tell me step by step don't simply write the answer
the answer is 588.74 how please tell me or send me the photo of answer
Answers
Answer:
I am getting 315.872 ...
kindly check the attachment
hope it helps
Given
- Outer dimensions of a closed box :-
- Length of the box = 15 cm
- Breadth of the box = 12 cm
- Height of the box = 9 cm
- Thickness of the iron all around the box = 0.8 cm
To find
- Volume of the iron used to make the closed box
Solution
Here, we see we have the values of the outer dimensions of the box. Firstly, we will find the volume of the box.
Using formula,
❖ Volume = lbh
where,
- l = length of the box
- b = breadth of the box
- h = height of the box
Substituting the values,
⟶ 15 × 12 × 9
⟶ 1620 cm³
Volume of the outer dimensions of the box = 1620 cm³
Now,
We will subtract (0.8 + 0.8) cm from the outer dimensions of the box. To get the inner dimensions of the box.
Inner dimensions of the box :-
- Length = 15 - (0.8 + 0.8) = 13.4 cm
- Breadth = 12 - (0.8 + 0.8) = 10.4 cm
- Height = 9 - (0.8 + 0.8) = 7.4 cm
Now, we will find the volume of the inner dimensions of the box.
Using formula,
❖ Volume = lbh
Substituting the values,
⟶ 13.4 × 10.4 × 7.4
⟶ 1,031.264 cm³
Volume of the inner dimensions of the box = 1,031.264 cm³
Now, to find the volume of iron used to make a closed box. We will subtract the volume of inner dimensions of the box from volume of the outer dimensions of the box.
❖ Volume of the iron used to make the box = Volume of the outer dimensions of the box - Volume of the inner dimensions of the box.
⟶ 1620 - 1,031.264
⟶ 588.736 cm³
❖ Therefore, volume of the iron used to make the box = 588.736 cm³