Find the volume of the solid generated by the revolution of the area bounded by the parabola y2=4x and the line 4x-3y=0,about the y-axis
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2
y
2
=4x⇒x=
4
y
2
2x−3y+4=0⇒x=
2
3
y−2
4
y
2
=
2
3
y−2
y
2
=6y−8
y
2
−6y+8=0
(y−4)(y−2)=0
y
1
=2,y
2
=4
A=∫
2
4
(
2
3
y−2)−(
4
y
2
)dy
=[
4
3y
2
−2y−
12
y
3
]
2
4
=
3
36−24−16−9+12+2
=
3
1
sq. units
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