Question

find the volume right circular cone with
radius 6 cm and height 70
cm​

Answer 1

GIVEN :-

• Radius of right circular cone is 6 cm.
• Height of right circular cone is 70 cm.

TO FIND :-

• The volume of right circular cone.

SOLUTION :-

☞ Volume = πr² × h/3

⇒πr² × h/3

⇒22/7 × (6)² × 70/3

⇒22/7 × 36 × 70/3

⇒22/7 × 12 × 70

⇒2640 cm³

Hence the volume of right circular cone is 2640 cm³

ADDITIONAL INFORMATION :-

⇒Lateral surface area of right circular cone = πr √(h² + r ²)

⇒Total surface area of right circular cone = π (r + l)r.

Answer 2

Question:

Find the volume right circular cone with radius 6 cm and height 70 cm.

To find:

$\bigstar Volume \: of \: the \: cone = ?$

Answer:

$\boxed{Volume \: of \: the \: cone \: is \: \underline{ \: \underline{ \: \sf \pink{ \bold{2640 {cm}^{3}} }} \: } \: }$

Given:

$\bigstar Radius \: of \: cone(r)=6cm$

$\bigstar Height \: of \: cone = 70cm$

Step-by-step explanation:

We know that,

$\boxed{Volume \: of \: the \: cone = \frac{1}{3}\pi {r}^{2}h}$

$The \: value \: of \: \underline{\pi \: is \: \frac{22}{7} }$

$\implies \frac{1}{3} \times \frac{22}{ \not{7}} \times {(6)}^{2} \times \not{ 70 }_{10}$

$\implies \frac{ 22 \times \not{36} _{12} \times 10}{ \not{3}}$

$\implies 22 \times 12 \times 10$

$\implies \boxed{2640{cm}^{3} }$

$\therefore Volume \: of \: the \: cone \: is \: 2640 {cm}^{3}$

Formula used:

$Volume \: of \: the \: cone = \frac{1}{3}\pi {r}^{2}h$

$Where$

$\star r \: is \: radius$

$\star h \: is \: height$

Basic informations of cone:

$\boxed{\bigstar C.S.A \: of \: the \: cone \: is \: \pi rl }$

$\boxed{ \bigstar T.S.A \: of \: the \: cone \: is \: \pi r(l + r)}$

$\boxed {\bigstar l = \sqrt{ {r}^{2} + {h}^{2} } }$

$Where$

$\star r \: is \: radius$

$\star l \: is \: slant \: height$