Question

find the volume that 35.2 g of carbon tetrachloride (CCI⁴) will occupy if it has a density of 1.60 g mL-¹​

Answer 1

CCl⁴

Given , mass = 35.2 g

Volume = Mass / Density

==> 35.2 / 1.60

==> 22 mL

Answer 2

$\blue{\bold{\underline{\underline{Answer:}}}}$

$\green{\tt{\therefore{Volume\:of\:CCl^{4}=22\:ml}}}$

$\orange{\bold{\underline{\underline{Step-by-step\:explanation:}}}}$

$\green{\underline\bold{Given : }} \\ \tt: \implies Mass \: of \: CCl^{4}(m)= 35.2 \:g\\ \\ \tt: \implies Density\: of \: CCl^{4}(\rho) = 1.6 { \:g/ml}^{1} \\ \\ \red{\underline\bold{To \: Find:}} \\ \tt: \implies Volume \: of \: CCl^{4}= ?$

• According to given question :

$\bold{As \: we \: know \: that } \\ \tt: \implies Density = \frac{Mass}{Volume} \\ \\ \tt: \implies 1.6 \: g {ml}^{ - 1} = \frac{35.2 \: g}{Volume} \\ \\ \tt: \implies Volume = \frac{35.2}{1.6} \times \frac{g}{g\times {ml}^{ - 1} } \\ \\ \tt: \implies Volume = \frac{352}{16} \times \frac{1}{ {ml}^{ - 1} } \\ \\ \green{\tt: \implies Volume = 22 \: ml} \\ \\ \green{\tt \therefore Volume \: of \: CCl ^{4} \: is \: 22 \: ml \: or \: 22 \: {cm}^{3} }$