Question

find the wavenumber of the photon having energy 2.072 electron volt
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Answer 1

$\huge\mathbb{QUESTION-}$

Find the wavenumber of the photon having energy 2.072 electron volt

$\huge\mathbb{SOLUTION-}$

$\large\underline{\underline{\sf Given:}}$

• Energy (E) = 2.072 eV

$\large\underline{\underline{\sf To\:Find:}}$

• Wavenumber ${\sf \dfrac{1}{\lambda}}$.

$\large\underline{\underline{\sf Formula\:Used:}}$

$\large{\boxed{\sf E=\dfrac{hc}{\lambda}}}$

$\implies{\sf \dfrac{1}{\lambda}=\dfrac{E}{hc}}$

$\implies{\sf \dfrac{2.072×1.6×10^{-19}}{6.63×10^{-34}×3×10^8} }$

$\implies{\sf \dfrac{3.315×10^{-19}}{19.89×10^{-26}} }$

$\implies{\bf \red{1.66×10^6\:m^{-1}}}$

$\huge\mathbb{ANSWER-}$

Wavenumber is ${\bf \red{1.66×10^6\:m^{-1}}}$