Question

find the weight of 6.02*10^25molecules of ca(oH)2

Answer 1

Answer:

7.4 kg

Explanation:

Mass of 1 mole of Ca(OH)2 = 74 g

By mole concept

we know that

6.02 × 10^23 molecules of Ca(OH)2 = 1 mole of Ca(OH)2

Therefore, 6.02 × 10^25 molecules of Ca(OH)2 = (6.02 × 10^25)÷(6.02 × 10^23) moles of Ca(OH)2

which comes to be 100

Now, 1 mole of Ca(OH)2 weighs = 74 g

100 moles of Ca(OH)2 will weigh = 74 ×100 g = 7400 g = 7.4 kg