Question

find the weight of a solid rectangular block of iron of size 50cm by 40cm by 10cm , if (1cm)3 of iron weighs 7.8g​

Answer 1

Answer :-

Weight = 1,56,000 g or 156 Kg

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Given :-

• A rectangular block of iron with Dimensions 50 × 40 × 10 .

• Weight of 1 cm³ Iron = 7.8 g

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To Find :-

• The weight of a solid rectangular block of Iron.

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Step By Step Solution :-

To Find the weight of Rectangular block of Iron

• First we will find the volume of cuboid.

☆Volume of Cuboid = Length × Breadth × Height

So Volume ⤵

$\implies50 \times 40 \times 10 \: \: {cm}^{3} \\ \\ \implies \: 20000 \: {cm}^{3}$

• Second we will multiply the volume by 7.8 g

Now Weight = Volume × 7.8 g

Weight ⤵

$\implies20000 \times 7.8 \\ \\ \implies 156000 \: g$

Therefore the weight of Iron = 1,56,000 g or 156 Kg

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