Question

Find the width of rectangle with perimeter 90 m and length 15m

Answer 1

$\huge\mathbb{SOLUTION:-}$

$\bold{Given}\begin{cases}\sf{perimeter\:of\: rectangle=90m}\\ \sf{length =15m}\end{cases}$

• we have to find the width of rectangle

$\bf\underline{According\:to\: Question:-}$

$\boxed{\sf{Perimeter\:of\: rectangle=2(l+b)}}$

$\sf \implies 90=2(15+b)\\ \\ \sf\implies 90=30+2b\\ \\ \sf\implies 90-30=2b\\ \\ \sf\implies 60=2b\\ \\ \sf\implies \cancel{\frac{60}{2}}=30=b$

• The breadth of rectangle is 30m

$\boxed{\sf{width=30m}}$

• Formula related rectangle:-

$\boxed{\sf{Perimeter\:of\: rectangle=2(l+b)}}$

$\boxed{\sf{Area\:of\: rectangle=l\times b}}$

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Answer 2

$\underline \mathbb{SOLUTION}$

$\underline \mathbb{GIVEN}$

》Perimeter of rectangle = 90 m

》Length = 15 m

To find,

》Width of rectangle

$\underline \mathbb{ATQ}$

PERIMETER = 2(l + b)

$= > 90 = 2(15 + b)$

$= > 90 = 30 + 2b$

$= > 90 -30 = 2b$

$= > 60 = 2b$

$= > \frac{60}{2} = 30$

$b = 30m$

$\underline \mathbb{WIDTH = 30}$

HENCE ,THE WIDTH IS 30 m.

_______________________________________

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